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python2.7中Csv库rEADEr报错

import csvwith open('eggs.csv', 'rb') as csvfile: spamreader = csv.reader(csvfile, delimiter=' ', quotechar='|') for row in spamreader: print ', '.join(row)我试了没问题,可能你输入的问题,你拷贝再试试。

拼写错误吧,第三行 fobj 换成 f 试试

把"list.csv"改成filename def csv2dict(fname): new_dict = {} with open(fname, 'rb') as f: reader = csv.reader(f, delimiter=',') fieldnames = next(reader) reader = csv.DictReader(f, fieldnames=fieldnames, delimiter=',') for row i...

reader = csv.reader(open('E:/BigData/tianchi_mobile_recommend_train_user.csv','r+')) \t是制表符,直接用/代表\避免 出现 "\t" "\n"这样的转 义符

input = {}with open('tst1.csv') as f: for line in f: key, field1, field2, field3 = line[:-1].split(',') input[key] = (key, field1, field2, field3) with open('tst2.csv') as fr, open('output.csv', w) as fw: for line in fr: key, f...

在python3使用read_csv的时候,如果传入的参数不是文件名而是文件的路径,就会报这个错。 原因应该是这个库的问题,解决方法是,先切换到这个目录,然后传文件名作为参数。 出错代码: import pandas as pd trainFile = "F:/Projects/Python/cou...

应该是误将float当作list或者tuple来操作了 对于list或者元组,[]操作是访问下标所在的元素,也就是__getitem__方法。 由于python定义变量的时候并不说明类型,类型都在运行时确定,因此有出现类型错误的可能性。 至于具体怎么修改,无法从你的...

用pandas库, import pandas as pddata = pd.read_csv('train.csv')train_data = data.values[0:TRAIN_NUM,1:]train_label = data.values[0:TRAIN_NUM,0] study.163.com/course/courseMain.htm?courseId=1000035 机器学习正好讲了这个手写识别的...

class DBI(object): """database interface""" def __init__(self, conn): """keep connection""" self._conn = conn def store(self, sql, data): """store data into database with given sql""" curr = self._conn.cursor() curr.executemany...

用csv模块 import csvcsvfile = file('test.csv', 'rb')reader = csv.reader(csvfile)for line in reader: print linecsvfile.close()

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