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求JS输出二维数组所有组合的函数

arr = [["A","B","C"],"D",["E","F"],["J","G","H","I"]];arr2 = [];function all_arrs(arr,level,former){if(arr.length == level + 1){if(arr[level] instanceof Array){for(var i = 0; i < arr[level].length; i++){temp = former.slice(0);t...

function doExchange(doubleArrays){ var len=doubleArrays.length; if(len>=2){ var len1=doubleArrays[0].length; var len2=doubleArrays[1].length; var newlen=len1*len2; var temp=new Array(newlen); var index=0; for(var i=0;i

var arrs=new Array(); var arr1=new Array(); arr1.push("a"); arr1.push("b"); arr1.push("c"); arrs.push(arr1); var arr2=new Array(); arr2.push("x"); arr2.push("y"); arr2.push("z"); arrs.push(arr2); for(var i=0;i

JS求二维数组的和 //定义一个一维数组 var arr = new Array(3); //将一维数组的各个元素定义为一维数组,从而构建出而为数组 for(var i=0;i

比如: var temp=[ ["Fu","Hai","Huan"], ["Wei","You"], ["Chong","Tong","Zhong"] ]; 每一个数组的长计都不确定 , 如何 遍历这个数组 得到如: FuWeiChong ,FuWeiTong这样的数据!

for循环 简单的一个函数 原生的真不知道

这不是数组,这是对象里面的数组或者,对象;我理解是数组,因为你的key,value不对应,然后还是写的逗号var menudata={"在线寄件":["在线下单","herf","批量下单","href"],"寄件记录":["订单历史","href","寄件运单"]};

$arr1 = array(1,2,3,4); $arr2 = array(a,b,c,d,); $arr3 = array_push($arr1,$arr2); print_r($arr3); array(1,2,3,4,a,b,c,d);

3: var myArray = new Array(3); 4: myArray[0] = “Item 0”; 5: myArray[1] = “Item 1”; 6: myArray[2] = “Item 2”; 7: for (i = 0; i < myArray.length; i++) { 8: document.write(myArray[i] + “”); 9: }

var da={"success": {"1": [{"t":"A4","c":"2017/7/3"}, {"t":"A2","c":"2017/7/3"},{"t":"A3","c":"2017/7/4"}, {"t":"A1","c":"2017/7/4"}], "2": [{"t":"B4","c":"2017/7/3"}, {"t":"B2","c":"2017/7/3"}, {"t":"B3","c":"2017/7/4"}, {"t":"...

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