prss.net
当前位置:首页 >> ∫x²sin³xDx换元怎么解 >>

∫x²sin³xDx换元怎么解

∫x²sin³xdx=1/4∫x²(3sinx-sin3x)dx =3/4∫x²sinxdx-1/4∫x²sin3xdx =-3/4∫x²dcosx+1/12∫x²dcos3x =-3/4x²cosx+3/4∫cosxdx²+1/12x²cos3x-1/12∫cos3xdx² =-3/4x²cosx+3/2∫xcosxdx+1/12...

(11)∫xln²(1+x²)/(1+x²)dx= 令t=1+x²,则dt=2xdx,xdx=1/2*dt ∫ln²t/t*1/2*dt= (1/t*dt=dlnt) 1/2*∫ln²tdlnt=1/6*ln³t+c=1/6*ln³(1+x²)+c (13)∫dx/(2+2x+x²)=∫dx/[(x+1)²+1]=∫d(x...

∫sin³xdx =∫sinx(1-cos²x)dx =∫(sinx-sinxcos²x)dx =-cosx+∫cos²xd(cosx) =-cosx-cos³x/3+C

∫x²sin³xdx=1/4∫x²(3sinx-sin3x)dx =3/4∫x²sinxdx-1/4∫x²sin3xdx =-3/4∫x²dcosx+1/12∫x²dcos3x =-3/4x²cosx+3/4∫cosxdx²+1/12x²cos3x-1/12∫cos3xdx² =-3/4x²cosx+3/2∫xcosxdx+1/12...

网站首页 | 网站地图
All rights reserved Powered by www.prss.net
copyright ©right 2010-2021。
内容来自网络,如有侵犯请联系客服。zhit325@qq.com