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∫sin^3x Cosx/³√sinx%Cosx Dx

解: sin³x-cos³x =(sinx-cosx)(sin²x+sinxcosx+cos²x) =(sinx-cosx)(1+sinxcosx) =sinx+sin²xcosx-cosx-sinxcos²x =sinx-cosx+½sinxsin2x-½cosxsin2x =sinx-cosx-¼(cos3x-cosx)-¼(sin3x+sin...

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